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(B) First,arrange the data in ascending order of magnitude and calculate the cumulative frequency $(cf)$:						Height (in $cm$)			$150$			$152$			$154

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$155$

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(B) First,arrange the data in ascending order of magnitude and calculate the cumulative frequency $(cf)$:						Height (in $cm$)			$150$			$152$			$154$			$155$			$156$			$160$			$161$							No of students $(f)$			$8$			$4$			$3$			$7$			$3$			$12$			$4$							Cumulative Frequency $(cf)$			$8$			$12$			$15$			$22$			$25$			$37$			$41$			Here,the total number of observations $N = 41$,which is an odd number.The median is the value of the $\left(\frac{N+1}{2}ight)^{	ext{th}}$ observation.Median $= \left(\frac{41+1}{2}ight)^{	ext{th}} = 21^{	ext{st}}$ observation.From the cumulative frequency table,we observe that the $21^{	ext{st}}$ observation falls in the range where the height is $155$ (since $cf$ for $154$ is $15$ and $cf$ for $155$ is $22$).Thus,the median is $155$.

The following data gives the distribution of height of students:

Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$

No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$

The median of the distribution is:

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Height (in $cm$)	$160$	$150$	$152$	$161$	$156$	$154$	$155$
No of students	$12$	$8$	$4$	$4$	$3$	$3$	$7$

The following data gives the distribution of height of students: Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$ No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$ The median of the distribution is: